3x^2-93x-285=0

Solution for 3x^2-93x-285=0 equation:

3x^2-93x-285=0

a = 3; b = -93; c = -285;
Δ = b2-4ac
Δ = -932-4·3·(-285)
Δ = 12069
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12069}=\sqrt{81*149}=\sqrt{81}*\sqrt{149}=9\sqrt{149}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-93)-9\sqrt{149}}{2*3}=\frac{93-9\sqrt{149}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-93)+9\sqrt{149}}{2*3}=\frac{93+9\sqrt{149}}{6}
$